If it's not what You are looking for type in the equation solver your own equation and let us solve it.
25a^2+41a-24=0
a = 25; b = 41; c = -24;
Δ = b2-4ac
Δ = 412-4·25·(-24)
Δ = 4081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-\sqrt{4081}}{2*25}=\frac{-41-\sqrt{4081}}{50} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+\sqrt{4081}}{2*25}=\frac{-41+\sqrt{4081}}{50} $
| x+5/4-10=8 | | 4(3)-5-6x=35 | | |3x-7|+5x=7x+12 | | k/5=-9/3 | | 2(x+3)=5(x-3)+2 | | 3(n-5)=6n-30 | | d–6=6 | | 10|c+6|=90 | | 6x^2+63x+120=0 | | n-n+96=180 | | 2(3x-5)-12=32 | | -6+1=-2+7k | | 1/x=-8 | | a÷11=-5 | | -6n20=2n+4(1-3)n | | 4(2d+9)=20-7d | | 5n+2=4n-20 | | –5+2z=3z | | Y+5=-1(-4x-3) | | -8n+4(1+5n)=-6n=14 | | 3=2n−3 | | 6.25+1.25r=31.75 | | D=9p-3 | | 7x+2(-7-16)=17 | | -9/2(x)=-9-5x | | 71=-8w | | -3x+3(2x+4)=27 | | (x-9)=4(9+1/3x) | | (6y+6)-(4+5y)=3 | | 8x+5=2x-2 | | (-9/2)x=-9-5x | | 3x÷4+9=11 |